(A) In the given figure, $\angle \mathrm{ADC}=\angle \mathrm{BCA}$; prove that $△\mathrm{ACB}\sim △\mathrm{ADC}$. Hence find $\mathrm{BD}$ if $\mathrm{AC}=8\mathrm{cm}$ and $\mathrm{AD}=3\mathrm{cm}$.
OR
(B) If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then prove that the other two sides are divided in the same ratio.